If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium oxide (CaO) are produced?
Practice Questions
1 question
Q1
If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium oxide (CaO) are produced?
5 g
10 g
8 g
7 g
The balanced equation is CaCO3 → CaO + CO2. The molar mass of CaCO3 is 100 g/mol and CaO is 56 g/mol. Thus, 10 g of CaCO3 produces (10 g / 100 g/mol) x 56 g/mol = 5.6 g of CaO.
Questions & Step-by-step Solutions
1 item
Q
Q: If 10 grams of calcium carbonate (CaCO3) decomposes, how many grams of calcium oxide (CaO) are produced?
Solution: The balanced equation is CaCO3 → CaO + CO2. The molar mass of CaCO3 is 100 g/mol and CaO is 56 g/mol. Thus, 10 g of CaCO3 produces (10 g / 100 g/mol) x 56 g/mol = 5.6 g of CaO.
Steps: 6
Step 1: Write down the chemical equation for the decomposition of calcium carbonate: CaCO3 → CaO + CO2.
Step 2: Calculate the molar mass of calcium carbonate (CaCO3). It is 40 (Ca) + 12 (C) + 48 (O3) = 100 grams per mole.
Step 3: Calculate the molar mass of calcium oxide (CaO). It is 40 (Ca) + 16 (O) = 56 grams per mole.
Step 4: Determine how many moles of CaCO3 are in 10 grams. Use the formula: moles = mass / molar mass. So, moles of CaCO3 = 10 g / 100 g/mol = 0.1 moles.
Step 5: Use the balanced equation to find out how many moles of CaO are produced. From the equation, 1 mole of CaCO3 produces 1 mole of CaO, so 0.1 moles of CaCO3 will produce 0.1 moles of CaO.
Step 6: Convert the moles of CaO back to grams. Use the formula: mass = moles x molar mass. So, mass of CaO = 0.1 moles x 56 g/mol = 5.6 grams.
