How many grams of solute are needed to prepare 0.5 L of a 1 M NaCl solution? (Molar mass of NaCl = 58.5 g/mol)

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Q: How many grams of solute are needed to prepare 0.5 L of a 1 M NaCl solution? (Molar mass of NaCl = 58.5 g/mol)

Solution: Mass of solute = moles × molar mass = 1 mol × 58.5 g/mol = 58.5 g. For 0.5 L, it is 0.5 mol × 58.5 g/mol = 29.25 g.

Steps: 8

Step 1: Understand that Molarity (M) is defined as moles of solute per liter of solution.
Step 2: Identify the desired molarity of the solution, which is 1 M (1 mole per liter).
Step 3: Determine the volume of the solution you want to prepare, which is 0.5 L.
Step 4: Calculate the number of moles of solute needed using the formula: Moles = Molarity × Volume.
Step 5: Substitute the values: Moles = 1 M × 0.5 L = 0.5 moles.
Step 6: Find the molar mass of NaCl, which is given as 58.5 g/mol.
Step 7: Calculate the mass of the solute needed using the formula: Mass = Moles × Molar Mass.
Step 8: Substitute the values: Mass = 0.5 moles × 58.5 g/mol = 29.25 g.