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How many grams of sodium chloride are needed to prepare 0.5 L of a 0.2 M solutio
How many grams of sodium chloride are needed to prepare 0.5 L of a 0.2 M solution?
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Practice Questions
1 question
Q1
How many grams of sodium chloride are needed to prepare 0.5 L of a 0.2 M solution?
5.84 g
11.68 g
2.92 g
0.58 g
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Molar mass of NaCl = 58.44 g/mol. Moles needed = 0.2 M * 0.5 L = 0.1 moles. Mass = moles * molar mass = 0.1 * 58.44 g = 5.844 g.
Questions & Step-by-step Solutions
1 item
Q
Q: How many grams of sodium chloride are needed to prepare 0.5 L of a 0.2 M solution?
Solution:
Molar mass of NaCl = 58.44 g/mol. Moles needed = 0.2 M * 0.5 L = 0.1 moles. Mass = moles * molar mass = 0.1 * 58.44 g = 5.844 g.
Steps: 6
Show Steps
Step 1: Understand that Molarity (M) is the number of moles of solute per liter of solution.
Step 2: Identify the desired concentration of the solution, which is 0.2 M.
Step 3: Identify the volume of the solution you want to prepare, which is 0.5 L.
Step 4: Calculate the number of moles needed using the formula: Moles = Molarity * Volume. So, Moles = 0.2 M * 0.5 L = 0.1 moles.
Step 5: Find the molar mass of sodium chloride (NaCl), which is 58.44 g/mol.
Step 6: Calculate the mass of sodium chloride needed using the formula: Mass = Moles * Molar Mass. So, Mass = 0.1 moles * 58.44 g/mol = 5.844 g.
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