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How many grams of NaOH are needed to neutralize 1 mole of HCl?
How many grams of NaOH are needed to neutralize 1 mole of HCl?
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Practice Questions
1 question
Q1
How many grams of NaOH are needed to neutralize 1 mole of HCl?
40 g
36.5 g
58.5 g
23 g
Show Solution
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The reaction between NaOH and HCl is 1:1. The molar mass of NaOH is 40 g/mol, so 1 mole of NaOH is needed, which weighs 40 g.
Questions & Step-by-step Solutions
1 item
Q
Q: How many grams of NaOH are needed to neutralize 1 mole of HCl?
Solution:
The reaction between NaOH and HCl is 1:1. The molar mass of NaOH is 40 g/mol, so 1 mole of NaOH is needed, which weighs 40 g.
Steps: 5
Show Steps
Step 1: Understand the reaction between NaOH and HCl. They react in a 1:1 ratio, meaning 1 mole of NaOH neutralizes 1 mole of HCl.
Step 2: Identify how many moles of HCl you have. In this case, we have 1 mole of HCl.
Step 3: Since the ratio is 1:1, you will need 1 mole of NaOH to neutralize 1 mole of HCl.
Step 4: Find the molar mass of NaOH. The molar mass is 40 grams per mole.
Step 5: Calculate the mass of NaOH needed. Since you need 1 mole of NaOH, you will need 40 grams.
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