For the reaction: 3A(g) ⇌ 2B(g) + C(g), what is the expression for Kp?
Practice Questions
1 question
Q1
For the reaction: 3A(g) ⇌ 2B(g) + C(g), what is the expression for Kp?
(P_B^2 * P_C) / (P_A^3)
(P_A^3) / (P_B^2 * P_C)
(P_C) / (P_A^3)
(P_B^2) / (P_A^3)
The equilibrium constant Kp is expressed as Kp = (P_B^2 * P_C) / (P_A^3).
Questions & Step-by-step Solutions
1 item
Q
Q: For the reaction: 3A(g) ⇌ 2B(g) + C(g), what is the expression for Kp?
Solution: The equilibrium constant Kp is expressed as Kp = (P_B^2 * P_C) / (P_A^3).
Steps: 5
Step 1: Identify the reaction: 3A(g) ⇌ 2B(g) + C(g).
Step 2: Write the general formula for the equilibrium constant Kp, which is based on the partial pressures of the gases involved.
Step 3: For each product, raise its partial pressure to the power of its coefficient in the balanced equation. Here, B has a coefficient of 2 and C has a coefficient of 1.
Step 4: For each reactant, raise its partial pressure to the power of its coefficient in the balanced equation. Here, A has a coefficient of 3.
Step 5: Combine these into the Kp expression: Kp = (P_B^2 * P_C) / (P_A^3).
