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Find the values of x that satisfy the equation sin^2(x) - sin(x) = 0.
Find the values of x that satisfy the equation sin^2(x) - sin(x) = 0.
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Practice Questions
1 question
Q1
Find the values of x that satisfy the equation sin^2(x) - sin(x) = 0.
0, π
0, π/2
0, 2π
0, 3π/2
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Factoring gives sin(x)(sin(x) - 1) = 0, so x = 0 and x = π.
Questions & Step-by-step Solutions
1 item
Q
Q: Find the values of x that satisfy the equation sin^2(x) - sin(x) = 0.
Solution:
Factoring gives sin(x)(sin(x) - 1) = 0, so x = 0 and x = π.
Steps: 7
Show Steps
Step 1: Start with the equation sin^2(x) - sin(x) = 0.
Step 2: Notice that this equation can be factored. Rewrite it as sin(x)(sin(x) - 1) = 0.
Step 3: Set each factor equal to zero. First, set sin(x) = 0.
Step 4: Solve sin(x) = 0. The solutions are x = 0, π, 2π, ... (any integer multiple of π).
Step 5: Now, set the second factor equal to zero: sin(x) - 1 = 0.
Step 6: Solve sin(x) - 1 = 0. The solution is sin(x) = 1, which occurs at x = π/2 + 2kπ (where k is any integer).
Step 7: Combine the solutions from both factors. The values of x that satisfy the equation are x = 0, π, and x = π/2 + 2kπ.
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