At what temperature will the RMS speed of a gas be 300 m/s if its molar mass is 28 g/mol?
Practice Questions
1 question
Q1
At what temperature will the RMS speed of a gas be 300 m/s if its molar mass is 28 g/mol?
300 K
600 K
900 K
1200 K
Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T. Setting v_rms = 300 m/s and M = 28 g/mol, we find T = (M * v_rms^2)/(3R) = 600 K.
Questions & Step-by-step Solutions
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Q
Q: At what temperature will the RMS speed of a gas be 300 m/s if its molar mass is 28 g/mol?
Solution: Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T. Setting v_rms = 300 m/s and M = 28 g/mol, we find T = (M * v_rms^2)/(3R) = 600 K.
Steps: 11
Step 1: Write down the formula for RMS speed: v_rms = sqrt((3RT)/M).
Step 2: Identify the values given in the problem: v_rms = 300 m/s and M = 28 g/mol.
Step 3: Rearrange the formula to solve for T: T = (M * v_rms^2) / (3R).
Step 4: Convert the molar mass M from grams per mole to kilograms per mole: M = 28 g/mol = 0.028 kg/mol.
Step 5: Use the value of the gas constant R = 8.314 J/(mol·K).
Step 6: Substitute the values into the rearranged formula: T = (0.028 kg/mol * (300 m/s)^2) / (3 * 8.314 J/(mol·K)).
Step 7: Calculate (300 m/s)^2 = 90000 m^2/s^2.
Step 8: Multiply 0.028 kg/mol by 90000 m^2/s^2 to get 2520 kg·m^2/(mol·s^2).
