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A uniform thin circular ring of mass M and radius R is rotated about an axis thr
A uniform thin circular ring of mass M and radius R is rotated about an axis through its center. What is its moment of inertia?
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Practice Questions
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Q1
A uniform thin circular ring of mass M and radius R is rotated about an axis through its center. What is its moment of inertia?
MR^2
1/2 MR^2
1/3 MR^2
2/5 MR^2
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The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Questions & Step-by-step Solutions
1 item
Q
Q: A uniform thin circular ring of mass M and radius R is rotated about an axis through its center. What is its moment of inertia?
Solution:
The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Steps: 5
Show Steps
Step 1: Understand what moment of inertia means. It is a measure of how difficult it is to change the rotation of an object.
Step 2: Identify the shape of the object. In this case, it is a uniform thin circular ring.
Step 3: Recognize that the mass of the ring is M and the radius is R.
Step 4: Recall the formula for the moment of inertia of a thin circular ring about an axis through its center, which is I = MR^2.
Step 5: Substitute the values of mass (M) and radius (R) into the formula to find the moment of inertia.
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