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A torque of 5 Nm is applied to a wheel. If the radius of the wheel is 0.25 m, wh
A torque of 5 Nm is applied to a wheel. If the radius of the wheel is 0.25 m, what is the force applied tangentially?
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Practice Questions
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Q1
A torque of 5 Nm is applied to a wheel. If the radius of the wheel is 0.25 m, what is the force applied tangentially?
10 N
20 N
5 N
15 N
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Torque (τ) = F × r, thus F = τ / r = 5 Nm / 0.25 m = 20 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A torque of 5 Nm is applied to a wheel. If the radius of the wheel is 0.25 m, what is the force applied tangentially?
Solution:
Torque (τ) = F × r, thus F = τ / r = 5 Nm / 0.25 m = 20 N.
Steps: 5
Show Steps
Step 1: Understand the formula for torque, which is τ = F × r, where τ is torque, F is force, and r is the radius.
Step 2: Identify the values given in the question: Torque (τ) = 5 Nm and Radius (r) = 0.25 m.
Step 3: Rearrange the formula to solve for force (F): F = τ / r.
Step 4: Substitute the values into the formula: F = 5 Nm / 0.25 m.
Step 5: Calculate the force: F = 20 N.
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