A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the concentration in terms of molarity? (Molar mass of NaCl = 58.5 g/mol)
Practice Questions
1 question
Q1
A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the concentration in terms of molarity? (Molar mass of NaCl = 58.5 g/mol)
1 M
2 M
0.5 M
0.25 M
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Questions & Step-by-step Solutions
1 item
Q
Q: A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the concentration in terms of molarity? (Molar mass of NaCl = 58.5 g/mol)
Solution: Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Steps: 7
Step 1: Identify the mass of NaCl you have, which is 58.5 grams.
Step 2: Find the molar mass of NaCl, which is given as 58.5 g/mol.
Step 3: Calculate the number of moles of NaCl using the formula: Moles = Mass (g) / Molar Mass (g/mol). So, Moles of NaCl = 58.5 g / 58.5 g/mol.
Step 4: Perform the calculation: 58.5 g / 58.5 g/mol = 1 mole of NaCl.
Step 5: Identify the volume of the solution, which is 1 liter (L).
Step 6: Calculate the molarity (M) using the formula: Molarity = Moles of solute / Volume of solution (L). So, Molarity = 1 mole / 1 L.
Step 7: Perform the calculation: 1 mole / 1 L = 1 M.
