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A simple harmonic oscillator has a mass of 2 kg and a spring constant of 200 N/m
A simple harmonic oscillator has a mass of 2 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
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Practice Questions
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Q1
A simple harmonic oscillator has a mass of 2 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
5 rad/s
10 rad/s
20 rad/s
15 rad/s
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The angular frequency ω is given by the formula ω = √(k/m). Here, k = 200 N/m and m = 2 kg. Thus, ω = √(200/2) = √100 = 10 rad/s.
Questions & Step-by-step Solutions
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Q
Q: A simple harmonic oscillator has a mass of 2 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
Solution:
The angular frequency ω is given by the formula ω = √(k/m). Here, k = 200 N/m and m = 2 kg. Thus, ω = √(200/2) = √100 = 10 rad/s.
Steps: 6
Show Steps
Step 1: Identify the formula for angular frequency, which is ω = √(k/m).
Step 2: Note the values given: the spring constant k is 200 N/m and the mass m is 2 kg.
Step 3: Substitute the values into the formula: ω = √(200/2).
Step 4: Calculate the value inside the square root: 200 divided by 2 equals 100.
Step 5: Take the square root of 100, which is 10.
Step 6: Conclude that the angular frequency ω is 10 rad/s.
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