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A rotating wheel has an angular momentum of 10 kg·m²/s. If its moment of inertia
A rotating wheel has an angular momentum of 10 kg·m²/s. If its moment of inertia is 2 kg·m², what is its angular velocity?
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Practice Questions
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Q1
A rotating wheel has an angular momentum of 10 kg·m²/s. If its moment of inertia is 2 kg·m², what is its angular velocity?
5 rad/s
10 rad/s
20 rad/s
2 rad/s
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Using L = Iω, we have ω = L/I = 10/2 = 5 rad/s.
Questions & Step-by-step Solutions
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Q
Q: A rotating wheel has an angular momentum of 10 kg·m²/s. If its moment of inertia is 2 kg·m², what is its angular velocity?
Solution:
Using L = Iω, we have ω = L/I = 10/2 = 5 rad/s.
Steps: 6
Show Steps
Step 1: Understand the formula for angular momentum, which is L = Iω, where L is angular momentum, I is moment of inertia, and ω is angular velocity.
Step 2: Identify the values given in the question: L (angular momentum) is 10 kg·m²/s and I (moment of inertia) is 2 kg·m².
Step 3: Rearrange the formula to solve for angular velocity (ω). The rearranged formula is ω = L/I.
Step 4: Substitute the values into the formula: ω = 10 kg·m²/s ÷ 2 kg·m².
Step 5: Perform the division: 10 ÷ 2 = 5.
Step 6: Conclude that the angular velocity (ω) is 5 rad/s.
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