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A point charge +Q is placed at the center of a spherical Gaussian surface of rad
A point charge +Q is placed at the center of a spherical Gaussian surface of radius R. What is the electric flux through the surface?
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Practice Questions
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Q1
A point charge +Q is placed at the center of a spherical Gaussian surface of radius R. What is the electric flux through the surface?
0
Q/ε₀
Q/(4πε₀R²)
Q/(4πε₀R)
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The electric flux through the Gaussian surface is given by Φ = Q/ε₀, where Q is the charge enclosed.
Questions & Step-by-step Solutions
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Q
Q: A point charge +Q is placed at the center of a spherical Gaussian surface of radius R. What is the electric flux through the surface?
Solution:
The electric flux through the Gaussian surface is given by Φ = Q/ε₀, where Q is the charge enclosed.
Steps: 4
Show Steps
Step 1: Identify the charge enclosed by the Gaussian surface. In this case, it is +Q.
Step 2: Recall the formula for electric flux (Φ) through a closed surface, which is Φ = Q/ε₀, where ε₀ is the permittivity of free space.
Step 3: Substitute the value of the enclosed charge (Q) into the formula: Φ = +Q/ε₀.
Step 4: Conclude that the electric flux through the spherical Gaussian surface is Φ = +Q/ε₀.
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