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A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What i
A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the period of the motion?
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Q1
A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the period of the motion?
2π s
4π s
10 s
20 s
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Period T = (2πr)/v = (2π * 10)/5 = 4π s.
Questions & Step-by-step Solutions
1 item
Q
Q: A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the period of the motion?
Solution:
Period T = (2πr)/v = (2π * 10)/5 = 4π s.
Steps: 7
Show Steps
Step 1: Understand the problem. We have a particle moving in a circle with a radius of 10 meters and a speed of 5 meters per second.
Step 2: Recall the formula for the period (T) of circular motion: T = (2πr) / v, where r is the radius and v is the speed.
Step 3: Plug in the values into the formula. Here, r = 10 m and v = 5 m/s.
Step 4: Calculate the circumference of the circle using the formula 2πr. So, 2π * 10 = 20π meters.
Step 5: Now, divide the circumference by the speed to find the period: T = (20π) / 5.
Step 6: Simplify the calculation: 20π / 5 = 4π seconds.
Step 7: Conclude that the period of the motion is 4π seconds.
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