A particle is moving in a circular path with a radius of 2 m and a speed of 3 m/s. What is the angular momentum of the particle if its mass is 4 kg?
Practice Questions
1 question
Q1
A particle is moving in a circular path with a radius of 2 m and a speed of 3 m/s. What is the angular momentum of the particle if its mass is 4 kg?
24 kg·m²/s
12 kg·m²/s
6 kg·m²/s
9 kg·m²/s
L = mvr = 4 kg * 3 m/s * 2 m = 24 kg·m²/s.
Questions & Step-by-step Solutions
1 item
Q
Q: A particle is moving in a circular path with a radius of 2 m and a speed of 3 m/s. What is the angular momentum of the particle if its mass is 4 kg?
Solution: L = mvr = 4 kg * 3 m/s * 2 m = 24 kg·m²/s.
Steps: 6
Step 1: Identify the given values. The mass (m) of the particle is 4 kg, the speed (v) is 3 m/s, and the radius (r) of the circular path is 2 m.
Step 2: Understand the formula for angular momentum (L). The formula is L = m * v * r.
Step 3: Substitute the values into the formula. Replace m with 4 kg, v with 3 m/s, and r with 2 m.
Step 4: Calculate the angular momentum. Multiply 4 kg by 3 m/s and then by 2 m: 4 * 3 * 2.
Step 5: Perform the multiplication. First, 4 * 3 = 12, then 12 * 2 = 24.
Step 6: Write the final answer. The angular momentum (L) is 24 kg·m²/s.
