A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?
Practice Questions
1 question
Q1
A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?
1/2
2/5
4/5
3/5
Total marbles = 5 + 3 + 2 = 10. Favorable outcomes (red or green) = 5 + 3 = 8. Probability = 8/10 = 4/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?
Solution: Total marbles = 5 + 3 + 2 = 10. Favorable outcomes (red or green) = 5 + 3 = 8. Probability = 8/10 = 4/5.
Steps: 7
Step 1: Count the number of red marbles. There are 5 red marbles.
Step 2: Count the number of green marbles. There are 3 green marbles.
Step 3: Count the number of blue marbles. There are 2 blue marbles.
Step 4: Add the total number of marbles together: 5 (red) + 3 (green) + 2 (blue) = 10 total marbles.
Step 5: Count the favorable outcomes, which are the red and green marbles: 5 (red) + 3 (green) = 8 favorable outcomes.
Step 6: Calculate the probability of drawing a red or green marble by dividing the number of favorable outcomes by the total number of marbles: 8 (favorable) / 10 (total) = 4/5.
Step 7: The final answer is that the probability of drawing a red or green marble is 4/5.
