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A hollow sphere rolls down an incline. If its mass is m and radius is R, what is
A hollow sphere rolls down an incline. If its mass is m and radius is R, what is its moment of inertia?
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Practice Questions
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Q1
A hollow sphere rolls down an incline. If its mass is m and radius is R, what is its moment of inertia?
(2/5)mR^2
(1/2)mR^2
(2/3)mR^2
(3/5)mR^2
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The moment of inertia of a hollow sphere about its center is I = (2/3)mR^2.
Questions & Step-by-step Solutions
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Q
Q: A hollow sphere rolls down an incline. If its mass is m and radius is R, what is its moment of inertia?
Solution:
The moment of inertia of a hollow sphere about its center is I = (2/3)mR^2.
Steps: 5
Show Steps
Step 1: Understand what a hollow sphere is. A hollow sphere is a spherical object that has a thin shell and is empty inside.
Step 2: Know that the moment of inertia is a measure of how difficult it is to change the rotation of an object.
Step 3: Identify the formula for the moment of inertia of a hollow sphere. The formula is I = (2/3)mR^2.
Step 4: Recognize that in the formula, 'm' represents the mass of the hollow sphere and 'R' represents its radius.
Step 5: Substitute the values of mass (m) and radius (R) into the formula if needed, but the general formula remains I = (2/3)mR^2.
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