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A door is pushed at its edge with a force of 20 N. If the width of the door is 0
A door is pushed at its edge with a force of 20 N. If the width of the door is 0.8 m, what is the torque about the hinges?
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Practice Questions
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Q1
A door is pushed at its edge with a force of 20 N. If the width of the door is 0.8 m, what is the torque about the hinges?
8 Nm
10 Nm
16 Nm
20 Nm
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Torque (τ) = Force (F) × Distance (r) = 20 N × 0.8 m = 16 Nm.
Questions & Step-by-step Solutions
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Q
Q: A door is pushed at its edge with a force of 20 N. If the width of the door is 0.8 m, what is the torque about the hinges?
Solution:
Torque (τ) = Force (F) × Distance (r) = 20 N × 0.8 m = 16 Nm.
Steps: 6
Show Steps
Step 1: Identify the force applied to the door. In this case, the force is 20 N.
Step 2: Identify the distance from the hinges to the point where the force is applied. The width of the door is 0.8 m.
Step 3: Use the formula for torque, which is Torque (τ) = Force (F) × Distance (r).
Step 4: Substitute the values into the formula: τ = 20 N × 0.8 m.
Step 5: Calculate the result: 20 N × 0.8 m = 16 Nm.
Step 6: The torque about the hinges is 16 Nm.
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