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A cylindrical Gaussian surface encloses a long straight wire carrying a current.
A cylindrical Gaussian surface encloses a long straight wire carrying a current. What is the electric field at a point outside the cylinder?
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Practice Questions
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Q1
A cylindrical Gaussian surface encloses a long straight wire carrying a current. What is the electric field at a point outside the cylinder?
Zero
Directly proportional to the distance from the wire
Inversely proportional to the distance from the wire
Constant
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The electric field outside the cylindrical surface is directly proportional to the distance from the wire.
Questions & Step-by-step Solutions
1 item
Q
Q: A cylindrical Gaussian surface encloses a long straight wire carrying a current. What is the electric field at a point outside the cylinder?
Solution:
The electric field outside the cylindrical surface is directly proportional to the distance from the wire.
Steps: 6
Show Steps
Step 1: Understand that we have a long straight wire carrying an electric current.
Step 2: Recognize that the wire creates an electric field around it.
Step 3: Identify that we are looking at a cylindrical Gaussian surface that surrounds the wire.
Step 4: Note that the electric field is strongest near the wire and decreases as you move away from it.
Step 5: Realize that the electric field at a point outside the cylinder depends on the distance from the wire.
Step 6: Conclude that the electric field outside the cylindrical surface is directly proportional to the distance from the wire.
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