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A charge of 5 μC is placed in an electric field of 2000 N/C. What is the electri
A charge of 5 μC is placed in an electric field of 2000 N/C. What is the electric potential energy of the charge?
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Q1
A charge of 5 μC is placed in an electric field of 2000 N/C. What is the electric potential energy of the charge?
10 mJ
1 mJ
0.5 mJ
2 mJ
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Electric potential energy (U) = Charge × Electric Field = 5 μC × 2000 N/C = 10 mJ.
Questions & Step-by-step Solutions
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Q
Q: A charge of 5 μC is placed in an electric field of 2000 N/C. What is the electric potential energy of the charge?
Solution:
Electric potential energy (U) = Charge × Electric Field = 5 μC × 2000 N/C = 10 mJ.
Steps: 6
Show Steps
Step 1: Understand the formula for electric potential energy (U), which is U = Charge × Electric Field.
Step 2: Identify the charge value, which is given as 5 μC (microcoulombs). Convert this to coulombs: 5 μC = 5 × 10^-6 C.
Step 3: Identify the electric field value, which is given as 2000 N/C.
Step 4: Plug the values into the formula: U = (5 × 10^-6 C) × (2000 N/C).
Step 5: Calculate the result: U = 5 × 2000 × 10^-6 = 10000 × 10^-6 = 0.01 J.
Step 6: Convert joules to millijoules: 0.01 J = 10 mJ.
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