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A charge of -4 μC is placed in an electric field of 200 N/C. What is the potenti
A charge of -4 μC is placed in an electric field of 200 N/C. What is the potential energy of the charge?
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Q1
A charge of -4 μC is placed in an electric field of 200 N/C. What is the potential energy of the charge?
-800 μJ
800 μJ
400 μJ
0 μJ
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Potential energy U = q * V = -4 × 10^-6 C * 200 N/C = -800 μJ.
Questions & Step-by-step Solutions
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Q
Q: A charge of -4 μC is placed in an electric field of 200 N/C. What is the potential energy of the charge?
Solution:
Potential energy U = q * V = -4 × 10^-6 C * 200 N/C = -800 μJ.
Steps: 6
Show Steps
Step 1: Identify the charge value. The charge is -4 μC, which is -4 x 10^-6 C.
Step 2: Identify the electric field strength. The electric field strength is 200 N/C.
Step 3: Use the formula for potential energy (U). The formula is U = q * V, where q is the charge and V is the electric field strength.
Step 4: Substitute the values into the formula. U = -4 x 10^-6 C * 200 N/C.
Step 5: Calculate the potential energy. Multiply -4 x 10^-6 by 200 to get -800 x 10^-6 J.
Step 6: Convert the result to microjoules (μJ). -800 x 10^-6 J is equal to -800 μJ.
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