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A charge of +3μC is placed at the origin. What is the electric potential at a po
A charge of +3μC is placed at the origin. What is the electric potential at a point 0.5m away?
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Practice Questions
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Q1
A charge of +3μC is placed at the origin. What is the electric potential at a point 0.5m away?
5400 V
1800 V
7200 V
3600 V
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V = k * q / r = (9 × 10^9) * (3 × 10^-6) / 0.5 = 54000 V.
Questions & Step-by-step Solutions
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Q
Q: A charge of +3μC is placed at the origin. What is the electric potential at a point 0.5m away?
Solution:
V = k * q / r = (9 × 10^9) * (3 × 10^-6) / 0.5 = 54000 V.
Steps: 7
Show Steps
Step 1: Identify the charge (q) which is +3μC. Convert this to coulombs: +3μC = 3 × 10^-6 C.
Step 2: Identify the distance (r) from the charge to the point where we want to find the electric potential. This distance is 0.5m.
Step 3: Use the formula for electric potential (V): V = k * q / r, where k is the electrostatic constant (approximately 9 × 10^9 N m²/C²).
Step 4: Substitute the values into the formula: V = (9 × 10^9) * (3 × 10^-6) / 0.5.
Step 5: Calculate the numerator: (9 × 10^9) * (3 × 10^-6) = 27,000.
Step 6: Divide the result by the distance (0.5): 27,000 / 0.5 = 54,000.
Step 7: Conclude that the electric potential at the point 0.5m away is 54,000 V.
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