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A charge of +10μC is placed at the origin. What is the electric potential at a p
A charge of +10μC is placed at the origin. What is the electric potential at a point 2m away from the charge?
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Practice Questions
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Q1
A charge of +10μC is placed at the origin. What is the electric potential at a point 2m away from the charge?
4500 V
2250 V
5000 V
1000 V
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V = k * q / r = (9 × 10^9) * (10 × 10^-6) / 2 = 4500 V.
Questions & Step-by-step Solutions
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Q
Q: A charge of +10μC is placed at the origin. What is the electric potential at a point 2m away from the charge?
Solution:
V = k * q / r = (9 × 10^9) * (10 × 10^-6) / 2 = 4500 V.
Steps: 7
Show Steps
Step 1: Identify the charge (q) which is +10μC. Convert this to coulombs: +10μC = +10 × 10^-6 C.
Step 2: Identify the distance (r) from the charge to the point where we want to find the electric potential. Here, r = 2m.
Step 3: Use the formula for electric potential (V): V = k * q / r, where k is the electrostatic constant (approximately 9 × 10^9 N m²/C²).
Step 4: Substitute the values into the formula: V = (9 × 10^9) * (10 × 10^-6) / 2.
Step 5: Calculate the numerator: (9 × 10^9) * (10 × 10^-6) = 90,000.
Step 6: Divide the result by the distance (2m): 90,000 / 2 = 45,000.
Step 7: Therefore, the electric potential (V) at the point 2m away from the charge is 4500 V.
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