A box is pushed with a force of 50 N on a surface with a coefficient of kinetic friction of 0.3. If the normal force is 100 N, what is the net force acting on the box?
Practice Questions
1 question
Q1
A box is pushed with a force of 50 N on a surface with a coefficient of kinetic friction of 0.3. If the normal force is 100 N, what is the net force acting on the box?
20 N
30 N
50 N
70 N
Frictional force = μk * N = 0.3 * 100 N = 30 N. Net force = applied force - frictional force = 50 N - 30 N = 20 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A box is pushed with a force of 50 N on a surface with a coefficient of kinetic friction of 0.3. If the normal force is 100 N, what is the net force acting on the box?
Solution: Frictional force = μk * N = 0.3 * 100 N = 30 N. Net force = applied force - frictional force = 50 N - 30 N = 20 N.
Steps: 9
Step 1: Identify the applied force on the box, which is given as 50 N.
Step 2: Identify the coefficient of kinetic friction, which is given as 0.3.
Step 3: Identify the normal force acting on the box, which is given as 100 N.
Step 4: Calculate the frictional force using the formula: Frictional force = μk * N.
Step 5: Substitute the values into the formula: Frictional force = 0.3 * 100 N.
Step 6: Calculate the frictional force: Frictional force = 30 N.
Step 7: Calculate the net force acting on the box using the formula: Net force = applied force - frictional force.
Step 8: Substitute the values into the formula: Net force = 50 N - 30 N.
Step 9: Calculate the net force: Net force = 20 N.
