A box contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is green given that it is not red?
Practice Questions
1 question
Q1
A box contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is green given that it is not red?
1/2
1/3
1/4
1/5
The total number of non-red marbles is 5 (3 green + 2 blue). The probability that the marble is green given that it is not red is P(Green | Not Red) = 3/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A box contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is green given that it is not red?
Solution: The total number of non-red marbles is 5 (3 green + 2 blue). The probability that the marble is green given that it is not red is P(Green | Not Red) = 3/5.
Steps: 5
Step 1: Count the total number of marbles in the box. There are 5 red, 3 green, and 2 blue marbles.
Step 2: Calculate the total number of non-red marbles. This is done by adding the number of green and blue marbles: 3 green + 2 blue = 5 non-red marbles.
Step 3: Identify how many of the non-red marbles are green. There are 3 green marbles.
Step 4: Calculate the probability of drawing a green marble given that it is not red. This is done by dividing the number of green marbles by the total number of non-red marbles: 3 green / 5 non-red = 3/5.
Step 5: State the final answer: The probability that the marble is green given that it is not red is 3/5.
