A box contains 10 balls, 4 of which are white and the rest are black. If one ball is drawn at random, what is the probability that it is not white?
Practice Questions
1 question
Q1
A box contains 10 balls, 4 of which are white and the rest are black. If one ball is drawn at random, what is the probability that it is not white?
2/5
3/5
4/5
1/5
The total number of balls is 10. The number of non-white balls is 10 - 4 = 6. Thus, the probability of drawing a non-white ball is 6/10 = 3/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A box contains 10 balls, 4 of which are white and the rest are black. If one ball is drawn at random, what is the probability that it is not white?
Solution: The total number of balls is 10. The number of non-white balls is 10 - 4 = 6. Thus, the probability of drawing a non-white ball is 6/10 = 3/5.
Steps: 6
Step 1: Identify the total number of balls in the box. There are 10 balls.
Step 2: Identify how many of those balls are white. There are 4 white balls.
Step 3: Calculate the number of non-white balls by subtracting the number of white balls from the total number of balls. This is 10 - 4 = 6 non-white balls.
Step 4: Write down the probability formula for drawing a non-white ball. Probability = (Number of non-white balls) / (Total number of balls).
Step 5: Substitute the numbers into the formula. This gives us Probability = 6 / 10.
Step 6: Simplify the fraction 6 / 10 to its simplest form, which is 3 / 5.
