A block of mass 5 kg is resting on a horizontal surface. If the coefficient of static friction is 0.4, what is the maximum static frictional force acting on the block?
Practice Questions
1 question
Q1
A block of mass 5 kg is resting on a horizontal surface. If the coefficient of static friction is 0.4, what is the maximum static frictional force acting on the block?
10 N
20 N
15 N
25 N
Maximum static frictional force (Fs) = μs * N = μs * mg = 0.4 * (5 kg * 10 m/s²) = 20 N.
Questions & Step-by-step Solutions
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Q
Q: A block of mass 5 kg is resting on a horizontal surface. If the coefficient of static friction is 0.4, what is the maximum static frictional force acting on the block?
Solution: Maximum static frictional force (Fs) = μs * N = μs * mg = 0.4 * (5 kg * 10 m/s²) = 20 N.
Steps: 7
Step 1: Identify the mass of the block, which is given as 5 kg.
Step 2: Identify the coefficient of static friction, which is given as 0.4.
Step 3: Calculate the weight of the block (N), which is the force due to gravity. Use the formula: N = mass * gravity. Here, gravity is approximately 10 m/s².
Step 4: Calculate the weight: N = 5 kg * 10 m/s² = 50 N.
Step 5: Use the formula for maximum static frictional force: Fs = μs * N.
Step 6: Substitute the values into the formula: Fs = 0.4 * 50 N.
Step 7: Calculate the maximum static frictional force: Fs = 20 N.
