A block of mass 10 kg is resting on a horizontal surface. If the coefficient of static friction is 0.5, what is the maximum static frictional force acting on the block?
Practice Questions
1 question
Q1
A block of mass 10 kg is resting on a horizontal surface. If the coefficient of static friction is 0.5, what is the maximum static frictional force acting on the block?
25 N
50 N
75 N
100 N
Maximum static frictional force (Fs) = μs * N = μs * mg = 0.5 * 10 kg * 9.8 m/s² = 49 N, approximately 50 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A block of mass 10 kg is resting on a horizontal surface. If the coefficient of static friction is 0.5, what is the maximum static frictional force acting on the block?
Solution: Maximum static frictional force (Fs) = μs * N = μs * mg = 0.5 * 10 kg * 9.8 m/s² = 49 N, approximately 50 N.
Steps: 8
Step 1: Identify the mass of the block. The mass is given as 10 kg.
Step 2: Identify the coefficient of static friction (μs). It is given as 0.5.
Step 3: Calculate the weight of the block (N), which is the force due to gravity. Use the formula: N = mass * gravity. Here, gravity (g) is approximately 9.8 m/s².
Step 4: Calculate the weight: N = 10 kg * 9.8 m/s² = 98 N.
Step 5: Use the formula for maximum static frictional force (Fs): Fs = μs * N.
Step 6: Substitute the values into the formula: Fs = 0.5 * 98 N.
Step 7: Calculate the maximum static frictional force: Fs = 49 N.
Step 8: Round the answer if necessary. The maximum static frictional force is approximately 50 N.
