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A ball is thrown vertically upwards with a speed of 15 m/s. What is the maximum
A ball is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
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Practice Questions
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Q1
A ball is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
11.5 m
15.0 m
22.5 m
30.0 m
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Using the formula h = v² / (2g), h = (15 m/s)² / (2 × 9.8 m/s²) = 11.5 m.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
Solution:
Using the formula h = v² / (2g), h = (15 m/s)² / (2 × 9.8 m/s²) = 11.5 m.
Steps: 8
Show Steps
Step 1: Identify the initial speed of the ball, which is 15 m/s.
Step 2: Identify the acceleration due to gravity, which is 9.8 m/s².
Step 3: Use the formula for maximum height, h = v² / (2g).
Step 4: Substitute the values into the formula: h = (15 m/s)² / (2 × 9.8 m/s²).
Step 5: Calculate (15 m/s)², which equals 225 m²/s².
Step 6: Calculate 2 × 9.8 m/s², which equals 19.6 m/s².
Step 7: Divide 225 m²/s² by 19.6 m/s² to find h.
Step 8: The result is approximately 11.5 m, which is the maximum height.
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