A ball is thrown horizontally from the top of a cliff with a speed of 15 m/s. If the cliff is 45 m high, how far from the base of the cliff will the ball land?
Practice Questions
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Q1
A ball is thrown horizontally from the top of a cliff with a speed of 15 m/s. If the cliff is 45 m high, how far from the base of the cliff will the ball land?
30 m
45 m
60 m
75 m
Time to fall = √(2h/g) = √(2*45/10) = 3 s. Horizontal distance = speed * time = 15 m/s * 3 s = 45 m.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown horizontally from the top of a cliff with a speed of 15 m/s. If the cliff is 45 m high, how far from the base of the cliff will the ball land?
Solution: Time to fall = √(2h/g) = √(2*45/10) = 3 s. Horizontal distance = speed * time = 15 m/s * 3 s = 45 m.
Steps: 8
Step 1: Identify the height of the cliff, which is 45 meters.
Step 2: Use the formula to find the time it takes for the ball to fall. The formula is time = √(2h/g), where h is the height and g is the acceleration due to gravity (approximately 10 m/s²).
Step 3: Plug in the values: time = √(2 * 45 / 10).
Step 4: Calculate the value inside the square root: 2 * 45 = 90, and then 90 / 10 = 9.
Step 5: Find the square root of 9, which is 3 seconds. This is the time it takes for the ball to hit the ground.
Step 6: Now, calculate how far the ball travels horizontally while it is falling. Use the formula: horizontal distance = speed * time.
Step 7: The speed of the ball is 15 m/s, and we found the time to be 3 seconds. So, horizontal distance = 15 m/s * 3 s.
