A ball is dropped from a height of 80 m. How long will it take to reach the ground?
Practice Questions
1 question
Q1
A ball is dropped from a height of 80 m. How long will it take to reach the ground?
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Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Rearranging gives t² = (2 * h) / g = (2 * 80) / 9.8 ≈ 16.33, so t ≈ 4.03 s.
Questions & Step-by-step Solutions
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Q
Q: A ball is dropped from a height of 80 m. How long will it take to reach the ground?
Solution: Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Rearranging gives t² = (2 * h) / g = (2 * 80) / 9.8 ≈ 16.33, so t ≈ 4.03 s.
Steps: 8
Step 1: Identify the height from which the ball is dropped. In this case, it is 80 meters.
Step 2: Know the acceleration due to gravity (g), which is approximately 9.8 meters per second squared (m/s²).
Step 3: Use the formula for the height of a falling object: h = 0.5 * g * t².
Step 4: Rearrange the formula to solve for time (t). This gives us t² = (2 * h) / g.
Step 5: Substitute the values into the rearranged formula: t² = (2 * 80) / 9.8.
Step 6: Calculate the right side: (2 * 80) = 160, so t² = 160 / 9.8.
Step 7: Perform the division: 160 / 9.8 ≈ 16.33.
Step 8: Take the square root of 16.33 to find t: t ≈ 4.03 seconds.
