A 5 kg block is placed on a surface with a coefficient of static friction of 0.6. What is the maximum static friction force before the block starts to move?
Practice Questions
1 question
Q1
A 5 kg block is placed on a surface with a coefficient of static friction of 0.6. What is the maximum static friction force before the block starts to move?
30 N
20 N
15 N
25 N
Maximum static friction force = μs * N = 0.6 * (5 kg * 9.8 m/s²) = 29.4 N, approximately 30 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A 5 kg block is placed on a surface with a coefficient of static friction of 0.6. What is the maximum static friction force before the block starts to move?
Solution: Maximum static friction force = μs * N = 0.6 * (5 kg * 9.8 m/s²) = 29.4 N, approximately 30 N.
Steps: 8
Step 1: Identify the mass of the block, which is 5 kg.
Step 2: Identify the coefficient of static friction, which is 0.6.
Step 3: Calculate the weight of the block using the formula: Weight (N) = mass (kg) * gravity (m/s²). Here, gravity is approximately 9.8 m/s².
Step 4: Calculate the weight: 5 kg * 9.8 m/s² = 49 N.
Step 5: Use the formula for maximum static friction force: Maximum static friction force = coefficient of static friction (μs) * normal force (N).
Step 6: Substitute the values: Maximum static friction force = 0.6 * 49 N.
Step 7: Calculate the maximum static friction force: 0.6 * 49 N = 29.4 N.
Step 8: Round the answer to the nearest whole number if needed: approximately 30 N.
