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A 3 kg object is lifted to a height of 5 m. What is the work done against gravit
A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
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Q1
A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
147 J
294 J
441 J
588 J
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Work done = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.
Questions & Step-by-step Solutions
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Q
Q: A 3 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
Solution:
Work done = mgh = 3 kg × 9.8 m/s² × 5 m = 147 J.
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 3 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = mgh.
Step 5: Substitute the values into the formula: Work = 3 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 3 × 9.8 = 29.4, then 29.4 × 5 = 147.
Step 7: The work done against gravity is 147 Joules (J).
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