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A 3 kg object is dropped from a height of 15 m. What is the potential energy at
A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?
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A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?
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Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 15 m = 441 J.
Questions & Step-by-step Solutions
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Q: A 3 kg object is dropped from a height of 15 m. What is the potential energy at the top?
Solution:
Potential energy = mass × g × height = 3 kg × 9.8 m/s² × 15 m = 441 J.
Steps: 6
Show Steps
Step 1: Identify the mass of the object. In this case, the mass is 3 kg.
Step 2: Identify the height from which the object is dropped. Here, the height is 15 m.
Step 3: Identify the acceleration due to gravity (g). The value of g is approximately 9.8 m/s².
Step 4: Use the formula for potential energy, which is: Potential energy = mass × g × height.
Step 5: Substitute the values into the formula: Potential energy = 3 kg × 9.8 m/s² × 15 m.
Step 6: Calculate the potential energy: 3 × 9.8 × 15 = 441 J.
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