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A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied,
A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)
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Practice Questions
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Q1
A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)
2 m/s²
3 m/s²
4 m/s²
5 m/s²
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Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².
Questions & Step-by-step Solutions
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Q
Q: A 3 kg object is at rest on a horizontal surface. If a force of 12 N is applied, what is the object's acceleration? (Assume no friction)
Solution:
Using F = ma, a = F/m = 12 N / 3 kg = 4 m/s².
Steps: 7
Show Steps
Step 1: Identify the mass of the object. The mass is given as 3 kg.
Step 2: Identify the force applied to the object. The force is given as 12 N.
Step 3: Recall the formula for acceleration, which is a = F/m, where 'a' is acceleration, 'F' is force, and 'm' is mass.
Step 4: Substitute the values into the formula. Here, F = 12 N and m = 3 kg.
Step 5: Calculate the acceleration: a = 12 N / 3 kg.
Step 6: Perform the division: 12 divided by 3 equals 4.
Step 7: Conclude that the object's acceleration is 4 m/s².
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