A 3 kg block is pulled with a force of 12 N. If the frictional force is 3 N, what is the acceleration of the block?

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Q: A 3 kg block is pulled with a force of 12 N. If the frictional force is 3 N, what is the acceleration of the block?

Solution: Net force = applied force - friction = 12 N - 3 N = 9 N. Acceleration a = F/m = 9 N / 3 kg = 3 m/s².

Steps: 9

Step 1: Identify the mass of the block, which is 3 kg.
Step 2: Identify the applied force, which is 12 N.
Step 3: Identify the frictional force, which is 3 N.
Step 4: Calculate the net force by subtracting the frictional force from the applied force: Net force = 12 N - 3 N.
Step 5: Perform the subtraction: 12 N - 3 N = 9 N. So, the net force is 9 N.
Step 6: Use the formula for acceleration, which is a = F/m, where F is the net force and m is the mass.
Step 7: Substitute the values into the formula: a = 9 N / 3 kg.
Step 8: Perform the division: 9 N / 3 kg = 3 m/s².
Step 9: Conclude that the acceleration of the block is 3 m/s².