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A 2 kg object is dropped from a height of 20 m. What is its potential energy at
A 2 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²)
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Practice Questions
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Q1
A 2 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²)
39.2 J
196 J
78.4 J
98.0 J
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Potential Energy (PE) = m × g × h = 2 kg × 9.8 m/s² × 20 m = 392 J.
Questions & Step-by-step Solutions
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Q
Q: A 2 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 9.8 m/s²)
Solution:
Potential Energy (PE) = m × g × h = 2 kg × 9.8 m/s² × 20 m = 392 J.
Steps: 6
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height from which the object is dropped. Here, the height (h) is 20 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = m × g × h.
Step 5: Substitute the values into the formula: PE = 2 kg × 9.8 m/s² × 20 m.
Step 6: Calculate the potential energy: 2 × 9.8 × 20 = 392 J.
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