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A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied,
A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
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Practice Questions
1 question
Q1
A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
2 m/s²
3 m/s²
4 m/s²
6 m/s²
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Using F = ma, acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Questions & Step-by-step Solutions
1 item
Q
Q: A 2 kg block is sliding on a frictionless surface. If a force of 6 N is applied, what is its acceleration?
Solution:
Using F = ma, acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Steps: 5
Show Steps
Step 1: Identify the mass of the block, which is 2 kg.
Step 2: Identify the force applied to the block, which is 6 N.
Step 3: Use the formula for acceleration, which is a = F/m.
Step 4: Substitute the values into the formula: a = 6 N / 2 kg.
Step 5: Calculate the acceleration: 6 N divided by 2 kg equals 3 m/s².
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