A 1 kg mass is dropped from a height of 10 m. What is its speed just before it hits the ground?

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Q: A 1 kg mass is dropped from a height of 10 m. What is its speed just before it hits the ground?

Solution: Using conservation of energy, v = √(2gh) = √(2 * 9.8 * 10) = 14 m/s.

Steps: 8

Step 1: Identify the mass of the object. In this case, the mass is 1 kg.
Step 2: Identify the height from which the object is dropped. Here, the height is 10 m.
Step 3: Understand that when the object is dropped, it will convert its potential energy at the height into kinetic energy just before it hits the ground.
Step 4: Use the formula for speed just before hitting the ground, which is v = √(2gh), where g is the acceleration due to gravity (approximately 9.8 m/s²) and h is the height (10 m).
Step 5: Plug in the values into the formula: v = √(2 * 9.8 * 10).
Step 6: Calculate the value inside the square root: 2 * 9.8 * 10 = 196.
Step 7: Take the square root of 196 to find the speed: √196 = 14 m/s.
Step 8: Conclude that the speed of the mass just before it hits the ground is 14 m/s.