A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when it is compressed by 0.1 m?
Practice Questions
1 question
Q1
A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when it is compressed by 0.1 m?
2 N
5 N
20 N
10 N
Using Hooke's law, F = kx = 200 N/m * 0.1 m = 20 N.
Questions & Step-by-step Solutions
1 item
Q
Q: A 1 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when it is compressed by 0.1 m?
Solution: Using Hooke's law, F = kx = 200 N/m * 0.1 m = 20 N.
Steps: 5
Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the amount the spring is compressed (x). Here, x = 0.1 m.
Step 3: Use Hooke's law formula, which is F = k * x.
Step 4: Substitute the values into the formula: F = 200 N/m * 0.1 m.
