A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring constant is 100 N/m, what is the potential energy stored in the spring?

1 question

1 item

Q: A 1 kg mass is attached to a spring and compressed by 0.2 m. If the spring constant is 100 N/m, what is the potential energy stored in the spring?

Solution: Potential energy in a spring is given by PE = 0.5kx². Thus, PE = 0.5 * 100 * (0.2)² = 2 J.

Steps: 7

Step 1: Identify the formula for potential energy stored in a spring, which is PE = 0.5 * k * x².
Step 2: Identify the values needed for the formula: the spring constant (k) is 100 N/m and the compression distance (x) is 0.2 m.
Step 3: Substitute the values into the formula: PE = 0.5 * 100 * (0.2)².
Step 4: Calculate (0.2)², which is 0.04.
Step 5: Multiply 100 by 0.04 to get 4.
Step 6: Multiply 4 by 0.5 to get 2.
Step 7: Conclude that the potential energy stored in the spring is 2 Joules.