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Q1. In a circuit with a 15V battery and a 5Ω resistor, what is the voltage drop across the resistor? (2019)
Solution:
The voltage drop across the resistor is equal to the battery voltage, which is 15V.
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Q2. In a circuit with a 24V battery and a total resistance of 8Ω, what is the power consumed by the circuit? (2023)
Solution:
Power P = V^2/R = 24^2/8 = 576/8 = 72 W.
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Q3. A circuit contains a 12V battery and two resistors of 4Ω and 6Ω in parallel. What is the total current supplied by the battery? (2019)
Solution:
First, find the equivalent resistance R_eq = 1/(1/4 + 1/6) = 2.4Ω. Then, I = V/R_eq = 12V/2.4Ω = 5 A.
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Q4. In a circuit with a 10Ω resistor and a 5Ω resistor in series, what is the total voltage across the circuit if the current is 2A? (2023)
Solution:
Total resistance R = 10Ω + 5Ω = 15Ω. Voltage V = I * R = 2A * 15Ω = 30V.
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Q5. If a circuit has a total resistance of 10Ω and a current of 3A, what is the voltage across the circuit? (2021)
Solution:
Using Ohm's law, V = I * R = 3A * 10Ω = 30V.
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Q6. What is the total current in a circuit with a 12V battery and two 6Ω resistors in series? (2021)
Solution:
Total resistance R = 6 + 6 = 12Ω. Current I = V/R = 12V/12Ω = 1A.
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Q7. If a circuit has a total resistance of 8Ω and a current of 2A flows through it, what is the voltage across the circuit? (2020)
Solution:
Using Ohm's law, V = I * R = 2A * 8Ω = 16V.
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Q8. If a circuit has a total voltage of 24V and a total resistance of 6Ω, what is the total current flowing through the circuit? (2023)
Solution:
Using Ohm's law, I = V/R = 24V/6Ω = 4A.
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Q9. If a circuit has a total voltage of 24V and a total resistance of 8Ω, what is the total current flowing through the circuit? (2023)
Solution:
Using Ohm's law, I = V/R = 24V/8Ω = 3A.
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Q10. In a series circuit, if one resistor fails, what happens to the current in the circuit? (2019)
Solution:
In a series circuit, if one resistor fails, the circuit is broken and the current stops.
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