Q1. An object is in free fall from a height of 80 m. How long will it take to reach the ground? (g = 9.8 m/s²)
Solution:
Using the formula s = ut + 0.5gt², where u = 0, s = 80 m, and g = 9.8 m/s², we solve 80 = 0 + 0.5 * 9.8 * t², giving t ≈ 4.04 s.
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Q2. What is the time taken for an object to fall from a height of 45 m under gravity?
Solution:
Using the formula h = 0.5 * g * t², we can rearrange to find t = √(2h/g). Substituting h = 45 m and g = 9.81 m/s² gives t ≈ 4.5 s.
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Q3. An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it rise before coming to a stop?
Solution:
Using the formula h = (v² - u²) / (2g), where v = 0, u = 20 m/s, and g = 9.81 m/s², we find h = (0 - (20)²) / (2 * -9.81) = 20.39 m, approximately 40 m.
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Q4. A car accelerates from rest at a rate of 2 m/s². How far does it travel in 5 seconds?
Solution:
Using the formula s = ut + 0.5at², where u = 0, a = 2 m/s², and t = 5 s, we get s = 0 + 0.5 * 2 * 5² = 25 m.
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Q5. What is the net force acting on a 5 kg object that is accelerating at 2 m/s²?
Solution:
Using Newton's second law, F = ma, where m = 5 kg and a = 2 m/s², we find F = 5 kg * 2 m/s² = 10 N.
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Q6. If a car accelerates from rest at a rate of 3 m/s², what is its velocity after 5 seconds?
Solution:
Using the formula v = u + at, where u = 0, a = 3 m/s², and t = 5 s, we get v = 0 + (3)(5) = 15 m/s.
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Q7. What is the formula for calculating the frictional force?
Solution:
The frictional force is calculated using the formula F_friction = μN, where μ is the coefficient of friction and N is the normal force.
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Q8. What is the net force acting on a 10 kg object that is accelerating at 3 m/s²?
Solution:
Using Newton's second law, F = ma, we find F = 10 kg * 3 m/s² = 30 N.
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Q9. A car travels 100 meters in 4 seconds. What is its average speed?
Solution:
Average speed = total distance / total time = 100 m / 4 s = 25 m/s.
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Q10. A ball is thrown vertically upwards with a speed of 20 m/s. How high will it go before it starts to fall back down? (g = 10 m/s²)
Solution:
Using the formula v² = u² + 2as, where v = 0, u = 20 m/s, and a = -10 m/s², we get 0 = 20² + 2 * (-10) * s, solving gives s = 20 m.
