Q1. What is the hybridization of the central atom in [Ni(CO)4]? (2022)
Solution:
In [Ni(CO)4], the nickel atom undergoes sp3 hybridization to accommodate four CO ligands.
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Q2. What is the coordination number of the central metal ion in the complex ion [Co(NH3)6]Cl3? (2021)
Solution:
In the complex ion [Co(NH3)6]Cl3, the central metal ion Co is surrounded by 6 ammonia (NH3) ligands, which gives it a coordination number of 6.
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Q3. What is the hybridization of the central metal ion in [Cr(NH3)6]3+? (2020) 2020
Solution:
In [Cr(NH3)6]3+, the hybridization is d2sp3 due to the octahedral arrangement of six ligands.
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Q4. Which of the following is a bidentate ligand? (2020) 2020
Solution:
EDTA can form multiple bonds with a metal ion, making it a bidentate ligand as it can attach at two sites.
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Q5. What is the coordination number of the metal ion in the complex [Co(NH3)5Cl]Cl2? (2023)
Solution:
In the complex [Co(NH3)5Cl]Cl2, cobalt is surrounded by five ammonia ligands and one chloride ligand, giving it a coordination number of 6.
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Q6. Which of the following complexes is paramagnetic? (2023) 2023
Solution:
[Fe(H2O)6]3+ has unpaired electrons, making it paramagnetic, while the others have all paired electrons.
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Q7. What is the coordination number of the complex ion [Co(NH3)5Cl]Cl2? (2023)
Solution:
In the complex [Co(NH3)5Cl]Cl2, cobalt is surrounded by five ammonia ligands and one chloride ligand, giving it a coordination number of 6.
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Q8. Which of the following complexes exhibits geometrical isomerism? (2022) 2022
Solution:
[CoCl2(NH3)4]+ can exhibit geometrical isomerism due to the different arrangements of ligands around the cobalt ion.
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Q9. What is the formula for the complex formed between iron(III) and thiocyanate? (2021)
Solution:
The complex formed is [Fe(SCN)3] as iron(III) can bond with three thiocyanate ions.
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Q10. What is the oxidation state of chromium in K2Cr2O7? (2021) 2021
Solution:
In K2Cr2O7, the total charge from potassium (K) is +2, and oxygen (O) contributes -14. Let the oxidation state of Cr be x. The equation is 2x - 14 + 2 = 0, solving gives x = +6.
