Q1. What is the effect of increasing the slit width in a single-slit diffraction experiment? (2021)
Solution:
Increasing the slit width decreases the fringe width because the angle of diffraction decreases.
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Q2. If the wavelength of light used in a single-slit diffraction experiment is increased, what happens to the width of the central maximum? (2023)
Solution:
The width of the central maximum in single-slit diffraction is directly proportional to the wavelength. Increasing the wavelength increases the width.
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Q3. If the wavelength of light used in a single-slit diffraction experiment is increased, what will happen to the position of the first minimum? (2022)
Solution:
The position of the first minimum in single-slit diffraction is given by a sin(θ) = λ. Increasing λ will cause θ to increase, moving the minimum away from the center.
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Q4. In a diffraction pattern, if the distance between the slits is decreased, what happens to the central maximum? (2022)
Solution:
Decreasing the distance between the slits increases the diffraction effect, causing the central maximum to become wider.
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Q5. A beam of light passes through a narrow slit and produces a diffraction pattern. What is the angle for the first minimum? (2022)
Solution:
The angle for the first minimum in single-slit diffraction is given by a sin θ = λ, hence θ = λ/a.
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Q6. In a thin film of oil on water, what color will be seen if the film thickness is such that destructive interference occurs for blue light? (2021)
Solution:
If destructive interference occurs for blue light, the color seen will be the complementary color, which is red.
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Q7. A beam of light passes through a narrow slit and produces a diffraction pattern. What is the angle of the first minimum? (2019)
Solution:
The angle of the first minimum in single-slit diffraction is given by sin(θ) = λ/a, where a is the width of the slit.
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Q8. A thin film of oil (n = 1.5) is on water (n = 1.33). What is the condition for destructive interference for light of wavelength 600 nm in air? (2022)
Solution:
For destructive interference in a thin film with a higher refractive index below, the condition is 2t = (m + 1/2)λ/n, where n is the refractive index of the film.
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Q9. In a thin film of oil on water, which color will appear at the center of the pattern if the film thickness is such that it causes constructive interference for red light? (2022)
Solution:
The color that appears at the center of the pattern corresponds to the wavelength that experiences constructive interference, which in this case is red light.
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Q10. In a diffraction pattern, the central maximum is observed to be the brightest. What is the reason for this? (2022)
Solution:
The central maximum has the maximum intensity because all light waves arrive in phase at this point, leading to constructive interference.