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Q1. A circuit has a 24V battery and a total resistance of 6Ω. What is the current flowing through the circuit? (2020)
Solution:
Using Ohm's law, I = V/R = 24V / 6Ω = 4A.
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Q2. What happens to the total current in a parallel circuit if one branch is removed? (2021)
Solution:
Removing a branch in a parallel circuit decreases the total current.
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Q3. What is the equivalent resistance of two resistors of 4Ω and 12Ω in parallel? (2022)
Solution:
Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/4 + 1/12 = 1/3, so R_eq = 3Ω.
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Q4. If a 100Ω resistor is connected in series with a 200Ω resistor, what is the total resistance? (2023)
Solution:
In series, R_total = R1 + R2 = 100Ω + 200Ω = 300Ω.
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Q5. In a parallel circuit with two resistors of 8Ω and 4Ω, what is the total current if the voltage across the circuit is 16V? (2022)
Solution:
First, find the equivalent resistance: 1/R_eq = 1/8 + 1/4 = 1/8 + 2/8 = 3/8, so R_eq = 8/3Ω. Then, I = V/R_eq = 16V / (8/3)Ω = 16 * 3/8 = 6A.
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Q6. In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
Solution:
Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.
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Q7. What is the voltage across a 12Ω resistor carrying a current of 3A? (2023)
Solution:
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
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Q8. If a circuit has a total resistance of 12Ω and a current of 3A flows through it, what is the voltage across the circuit? (2020)
Solution:
Using Ohm's law, V = IR = 3A * 12Ω = 36V.
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Q9. A resistor of 10Ω is connected across a 20V battery. What is the power consumed by the resistor? (2021)
Solution:
Power (P) is given by P = V^2/R = 20V^2 / 10Ω = 400W / 10 = 40W.
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Q10. If a 5Ω resistor is connected in series with a 10Ω resistor, what is the total resistance? (2022)
Solution:
In series, R_eq = R1 + R2 = 5Ω + 10Ω = 15Ω.
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