Q1. A dipole is placed in a uniform electric field. What is the torque experienced by the dipole? (2023)
Solution:
The torque (τ) experienced by a dipole in a uniform electric field is given by τ = pE sin(θ), where p is the dipole moment and θ is the angle between p and E.
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Q2. What is the effect of a dielectric material on the capacitance of a capacitor? (2023)
Solution:
Inserting a dielectric material increases the capacitance of a capacitor by reducing the electric field within it.
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Q3. If a charge of +2μC is placed in an electric field of 1000 N/C, what is the force experienced by the charge? (2023)
Solution:
The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 1000 N/C = 2 N.
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Q4. A dipole consists of two equal and opposite charges separated by a distance 'd'. What is the dipole moment? (2023)
Solution:
The dipole moment (p) is defined as p = qd, where q is the charge and d is the separation distance.
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Q5. A charge of +4 µC is placed in a uniform electric field of strength 500 N/C. What is the work done in moving the charge 0.2 m in the direction of the field?
Solution:
W = F * d = (E * q) * d = (500 N/C * 4 × 10^-6 C) * 0.2 m = 0.4 J.
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Q6. What is the electric potential at a point due to a charge Q at a distance r? (2021)
Solution:
The electric potential (V) at a distance r from a point charge Q is given by V = kQ/r.
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Q7. What is the force between two charges of +2μC and -3μC separated by 0.5m? (2022)
Solution:
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (9 × 10^9) * (2 × 10^-6) * (3 × 10^-6) / (0.5)^2 = 0.24 N.
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Q8. What is the capacitance of a capacitor that stores 10 µC of charge at a potential difference of 5 V?
Solution:
C = Q/V = 10 × 10^-6 C / 5 V = 2 × 10^-6 F = 2 µF.
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Q9. What is the force between two point charges of +2 µC and -3 µC separated by a distance of 0.5 m in vacuum?
Solution:
Using Coulomb's law, F = k * |q1 * q2| / r^2 = (9 × 10^9) * |2 × 10^-6 * -3 × 10^-6| / (0.5)^2 = -24 N.
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Q10. If a charge of +2μC is placed in an electric field of strength 500 N/C, what is the force experienced by the charge? (2022)
Solution:
The force (F) on a charge in an electric field is given by F = qE. Here, F = 2μC * 500 N/C = 1000 N.
