Q1. What is the root mean square speed of nitrogen gas (N2) at 300 K? (Molar mass of N2 = 28 g/mol)
Solution:
The root mean square speed is given by the formula v_rms = sqrt(3RT/M), where R = 8.314 J/(mol·K), T = 300 K, and M = 0.028 kg/mol. v_rms = sqrt(3 * 8.314 * 300 / 0.028) ≈ 500 m/s.
⏱ Time: 0s
Q2. In an ideal gas, what happens to the pressure if the volume is halved while keeping the temperature constant?
Solution:
According to Boyle's Law, if the volume is halved at constant temperature, the pressure doubles.
⏱ Time: 0s
Q3. Which of the following processes is an example of heat transfer by conduction?
Solution:
Heating a metal rod is an example of heat transfer by conduction.
⏱ Time: 0s
Q4. Which of the following is NOT a thermodynamic process?
Solution:
All listed processes are thermodynamic processes; however, 'Isobaric' is often confused with 'Isothermal' but is indeed a valid process.
⏱ Time: 0s
Q5. What is the root mean square speed of gas molecules at a temperature of 300 K for a gas with a molar mass of 0.029 kg/mol?
Solution:
Using the formula v_rms = sqrt(3RT/M), where R = 8.314 J/(mol·K), T = 300 K, and M = 0.029 kg/mol, we find v_rms ≈ 400 m/s.
⏱ Time: 0s
Q6. In a Carnot engine operating between 500 K and 300 K, what is the maximum efficiency?
