Electric Potential and Capacitance

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Q1. If the capacitance of a capacitor is doubled, what happens to the charge stored if the voltage remains constant?

Solution:

Capacitance (C) is defined as C = Q/V. If C is doubled and V remains constant, Q must also double.

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Q2. What is the relationship between voltage (V), current (I), and resistance (R) according to Ohm's Law?

Solution:

According to Ohm's Law, the relationship is V = I * R.

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Q3. If two capacitors of capacitance C1 and C2 are connected in series, what is the equivalent capacitance (Ceq)?

Solution:

The equivalent capacitance for capacitors in series is given by Ceq = 1 / (1/C1 + 1/C2).

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Q4. If the capacitance of a capacitor is doubled while the voltage remains constant, what happens to the charge stored?

Solution:

Charge (Q) stored in a capacitor is given by Q = C * V. If C is doubled and V remains constant, Q also doubles.

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Q5. What happens to the electric potential energy when a positive charge moves away from another positive charge?

Solution:

As a positive charge moves away from another positive charge, the electric potential energy decreases due to the repulsive force.

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Q6. If two capacitors are connected in series, how is the total capacitance (C_total) calculated?

Solution:

For capacitors in series, the total capacitance is given by 1/C_total = 1/C1 + 1/C2.

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Q7. What is the electric potential (V) at a distance (r) from a point charge (Q)?

Solution:

The electric potential due to a point charge is given by V = k * Q / r, where k is Coulomb's constant.

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Q8. What is the electric field (E) due to a point charge (Q) at a distance (r)?

Solution:

The electric field due to a point charge is given by E = k * Q / r^2.

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Q9. What is the formula for the energy stored in a capacitor?

Solution:

The energy (U) stored in a capacitor is given by U = 1/2 C V^2.