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Q1. What is the potential difference across a capacitor of 2 microfarads charged to 10 volts?
A
. 20 mC
B
. 0.02 C
C
. 0.02 mC
D
. 0.2 C
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Solution:
The charge (Q) on a capacitor is given by Q = C * V. Here, Q = 2 x 10^-6 F * 10 V = 20 x 10^-6 C = 20 mC.
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Q2. A circuit has a total voltage of 12V and a total resistance of 3 ohms. What is the total current in the circuit?
A
. 4 A
B
. 3 A
C
. 2 A
D
. 1 A
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Solution:
Using Ohm's Law, I = V/R. Here, I = 12V / 3Ω = 4 A.
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Q3. If two capacitors of 4 µF and 6 µF are connected in parallel, what is the total capacitance?
A
. 10 µF
B
. 24 µF
C
. 2.4 µF
D
. 12 µF
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Solution:
C_eq = C1 + C2 = 4 µF + 6 µF = 10 µF.
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Q4. What is the total current in a circuit with a 12 V battery and a total resistance of 4 Ω?
A
. 3 A
B
. 4 A
C
. 6 A
D
. 2 A
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Solution:
Using Ohm's Law: I = V / R = 12 V / 4 Ω = 3 A.
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Q5. What is the current through a 15 ohm resistor connected to a 45V source?
A
. 3 A
B
. 2 A
C
. 1 A
D
. 4 A
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Solution:
Using Ohm's Law, I = V/R. Here, I = 45V / 15Ω = 3 A.
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Q6. What is the equivalent resistance of three resistors of 4 ohms, 6 ohms, and 12 ohms connected in series?
A
. 22 ohms
B
. 12 ohms
C
. 10 ohms
D
. 8 ohms
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Solution:
In series, R_eq = R1 + R2 + R3 = 4Ω + 6Ω + 12Ω = 22Ω.
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Q7. What is the electric field (E) at a distance of 2 meters from a point charge of 5 microcoulombs?
A
. 1125 N/C
B
. 450 N/C
C
. 225 N/C
D
. 900 N/C
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Solution:
Using Coulomb's law, E = k * |q| / r^2, where k = 8.99 x 10^9 N m^2/C^2, q = 5 x 10^-6 C, and r = 2 m. E = (8.99 x 10^9) * (5 x 10^-6) / (2^2) = 1125 N/C.
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Q8. In a parallel circuit with two resistors of 6 ohms and 12 ohms, what is the equivalent resistance?
A
. 4 ohms
B
. 8 ohms
C
. 2 ohms
D
. 3 ohms
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Solution:
For parallel resistors, 1/R_eq = 1/R1 + 1/R2. Here, 1/R_eq = 1/6 + 1/12 = 2/12 + 1/12 = 3/12, so R_eq = 4 ohms.
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Q9. What is the current flowing through a 20 Ω resistor when a voltage of 100 V is applied?
A
. 5 A
B
. 10 A
C
. 15 A
D
. 20 A
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Solution:
Using Ohm's Law: I = V / R = 100 V / 20 Ω = 5 A.
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Q10. What is the electric field strength between two parallel plates separated by 0.1 m with a potential difference of 100 V?
A
. 1000 N/C
B
. 500 N/C
C
. 100 N/C
D
. 2000 N/C
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Solution:
The electric field (E) is given by E = V/d. Here, E = 100V / 0.1m = 1000 N/C.
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