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Q1. What is the electric field (E) at a distance of 2 meters from a point charge of 5 microcoulombs?
Solution:
Using Coulomb's law, E = k * |q| / r^2, where k = 8.99 x 10^9 N m^2/C^2, q = 5 x 10^-6 C, and r = 2 m. E = (8.99 x 10^9) * (5 x 10^-6) / (2^2) = 1125 N/C.
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